(b) The solution that remained after electrolysis in (a) was tested with litmus solution.
(i) State what was observed.
(ii) Give a reason for your answer in (b) (i)
(c) the electrolysis in (a) was repeated using copper electrodes that had been weighed before the experiment. State the change in mass of the electrode that took place after the electrolysis.
Suggested answers
(a) When an aqueous solution of copper (II) sulfate is electrolyzed between graphite electrodes:
(i) At the cathode, copper ions (Cu
2+) from the solution are reduced to form copper metal (Cu).
Cu
2+ + 2e
- → Cu (reduction)
Therefore, the observation would be the formation of a brown coating on the cathode as the copper metal is deposited.
(ii) At the anode, both sulphate ions (SO
42- and hydoxide ions (OH
- will migrate to it, but hydroxide will be selectively discharged.
4OH
- → 2H
2O + O
2 + 4e
-
(b) After electrolysis, the solution is tested with litmus solution:
(i) The litmus solution would turn red. This indicates that the solution has become acidic.
(ii) The reason for the solution turning acidic is due to the presence of hydrogen ions (H
+) which is remained in the solution during the electrolysis process. These hydrogen ions increase the acidity of the solution, turning the litmus solution red.
(c) When the electrolysis is repeated using copper electrodes that had been weighed before the experiment, the change in mass of the electrode that took place after the electrolysis would be as follows:
- The cathode would gain mass due to the deposition of copper metal from the solution.
- The anode would lose mass as copper from the electrode is oxidized and enters the solution as copper ions (Cu
2+).