193000C → 22.4dm3
? C → 100dm3
Q = 193000C X 100dm3 22.4dm3 = 861607C
From
Q = I.t
I = Q
t
Therefore:
I = 861607C
3600s
= 239.34A
m = Ar.I.t
v.F
I = m.v.F
Ar.t
but mass = volume of a gas x molar mass
molar volume
=100dm3 x 71g/mol 22.4dm3 mass = 316.964g
I = 316.964g x 1 x 96500C
35.5 x 3600s
I= 239.34A
The current 239.34A should be allowed to meet this demand.