193000C → 22.4dm3 ? C → 100dm3
Q = 193000C X 100dm3 22.4dm3 = 861607C
From
Q = I.tI = Q tTherefore:
I = 861607C 3600s= 239.34A
m = Ar.I.t v.F
I = m.v.F Ar.tbut
mass = volume of a gas x molar mass molar volume
=100dm3 x 71g/mol 22.4dm3 mass = 316.964g
I = 316.964g x 1 x 96500C 35.5 x 3600sI= 239.34A
The current 239.34A should be allowed to meet this demand.